![]() I'm not going to go into detail because I was describing prototypes, but the class syntax is a sugar-coated syntax for prototype-based inheritance. If you use it, you can inherit without using prototypes. 14 hours ago &0183 &32 A drawback that I see with this special treatment is that it prevents one from simply declaring non-function properties in the instances’ prototype, forcing one to do it after class declaration (or resort to a static initialization block): > A.prototype.y2 0 0 > Object.getOwnPropertyNames(A. Using prototypes solves this problem because you can have an implicit reference.īy the way, class syntax is available from ES2015. In JavaScript, every instance of an object is a copy.Īdding methods directly to the constructor will create as many methods as there are instances created, which will consume a lot of memory. There are many reasons for this, so if you are curious, please look into it. ![]() As friends array exists on Person. ![]() In this example, I extended the prototype of the Object object, which is a built-in object, but basically it is not a good idea to touch the built-in object. In the above example, person1 and person2 point to the same friends array of the prototype object.person1 modifies friends property by adding another string in the array. ![]()
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